C++ Structure and Function

C++ Tutorial

C++ Introduction

• C++ Variables and Literals
• C++ Data Types
• C++ Basic I/O
• C++ Type Conversion
• C++ Operators
• C++ Comments

C++ Flow Control

• C++ if…else
• C++ for Loop
• C++ do…while Loop
• C++ break & continue
• C++ switch Statement
• C++ goto Statement

C++ Functions

• C++ Functions
• C++ Function Types
• C++ Function Overloading
• C++ Default Argument
• C++ Storage Class
• C++ Recursion

C++ Arrays & String

• C++ Arrays
• Multidimensional Arrays
• C++ Function and Array
• C++ String

C++ Structures

• C++ Structure
• Structure and Function
• C++ Pointers to Structure
• C++ Enumeration

C++ Object & Class

• C++ Objects and Class
• C++ Constructors
• C++ Objects & Function
• C++ Operator Overloading

C++ Pointers

• C++ Pointer
• C++ Pointers and Arrays
• C++ Pointers and Functions

C++ Inheritance

• C++ Inheritance
• Inheritance Access Control
• C++ Function Overriding
• Multiple & Multilevel Inheritance
• C++ Friend Function
• C++ Virtual Function

In this article, you’ll find relevant examples to pass structures as an argument to a function, and use them in your program.

Structure variables can be passed to a function and returned in a similar way as normal arguments.

Passing structure to function in C++

A structure variable can be passed to a function in similar way as normal argument. Consider this example:

---

Example 1: C++ Structure and Function

#include <iostream>
using namespace std;

struct Person
{
    char name[50];
    int age;
    float salary;
};

void displayData(Person);   // Function declaration

int main()
{
    Person p;

    cout << "Enter Full name: ";
    cin.get(p.name, 50);
    cout << "Enter age: ";
    cin >> p.age;
    cout << "Enter salary: ";
    cin >> p.salary;

    // Function call with structure variable as an argument
    displayData(p);

    return 0;
}

void displayData(Person p)
{
    cout << "\nDisplaying Information." << endl;
    cout << "Name: " << p.name << endl;
    cout <<"Age: " << p.age << endl;
    cout << "Salary: " << p.salary;
}

Output

Enter Full name: Bill Jobs
Enter age: 55
Enter salary: 34233.4

Displaying Information.
Name: Bill Jobs
Age: 55
Salary: 34233.4

In this program, user is asked to enter the name, age and salary of a Person inside main() function.

Then, the structure variable p is to passed to a function using.

displayData(p);

The return type of displayData() is void and a single argument of type structure Person is passed.

Then the members of structure p is displayed from this function.

---

Example 2: Returning structure from function in C++

#include <iostream>
using namespace std;

struct Person {
    char name[50];
    int age;
    float salary;
};

Person getData(Person); 
void displayData(Person); 

int main()
{

    Person p;

    p = getData(p);   
    displayData(p);

    return 0;
}

Person getData(Person p) {

    cout << "Enter Full name: ";
    cin.get(p.name, 50);

    cout << "Enter age: ";
    cin >> p.age;

    cout << "Enter salary: ";
    cin >> p.salary;

    return p;
}

void displayData(Person p)
{
    cout << "\nDisplaying Information." << endl;
    cout << "Name: " << p.name << endl;
    cout <<"Age: " << p.age << endl;
    cout << "Salary: " << p.salary;
}

The output of this program is same as program above.

In this program, the structure variable p of type structure Person is defined under main() function.

The structure variable p is passed to getData() function which takes input from user which is then returned to main function.

p = getData(p); 

Note: The value of all members of a structure variable can be assigned to another structure using assignment operator = if both structure variables are of same type. You don’t need to manually assign each members.

Then the structure variable p is passed to displayData() function, which displays the information.

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